Suppress or exclude messages from /var/log/audit.log via audit.rules

Hi My name is Takehara liveng in japan. Now I set up audit.rules, then audit.log became very big. The reason why is keepalived daemon and it's misc check shell adds some entry every seconds. I want to suppress or exclude log entry, and I searched the way like this. => https://www.redhat.com/archives/linux-audit/2011-October/msg00000.html but I could not get effective answer. Could you please tell me someone an effective way? This is the audit.rules below. # First rule - delete all - keepalived is checking every seconds. /usr/sbin/keepalived - misc check program /root/mysql_status_check.sh type=SYSCALL msg=audit(1427989933.878:3632254): arch=c000003e syscall=2 success=yes exit=0 a0=4378a2 a1=2 a2=9 a3=8 items=1 ppid=43118 pid=3379 auid=501 uid=0 gid=0 euid=0 suid=0 fsuid=0 egid=0 sgid=0 fsgid=0 tty=(none) ses=3 comm="keepalived" exe="/usr/sbin/keepalived" key=(null) type=SYSCALL msg=audit(1427918414.323:2598129): arch=c000003e syscall=2 success=no exit=-6 a0=4a3155 a1=802 a2=1 a3=7fff4aefd1a0 items=1 ppid=20915 pid=20917 auid=501 uid=0 gid=0 euid=0 suid=0 fsuid=0 egid=0 sgid=0 fsgid=0 tty=(none) ses=3 comm="mysql_status_ch" exe="/bin/bash" key=(null) type=SYSCALL msg=audit(1427918414.341:2598135): arch=c000003e syscall=2 success=yes exit=3 a0=f14470 a1=241 a2=1b6 a3=76 items=2 ppid=20916 pid=20947 auid=501 uid=0 gid=0 euid=0 suid=0 fsuid=0 egid=0 sgid=0 fsgid=0 tty=(none) ses=3 comm="mysql_status_ch" exe="/bin/bash" key=(null) ========================= Cloud ASIA Co., Ltd. [ 株式会社クラウドエイジア ] Founder & CEO Takehara Toshihiro 〒174-0073 33-14-101, Higashiyama-cho, Itabashi-ku, Tokyo, Japan TEL: +81-3-6869-2994 FAX: +81-3-6869-3974 Mobile: +81-90-4737-8137 Mobile in Laos: +856-20-5912-2188 http://www.cloud-asia.co.jp http://www.facebook.com/cloud.asia.japan takehara(a)cloud-asia.co.jp Lao Systems [ ラオシステムズ ] Founder & CEO Takehara Toshihiro http://lao-systems.jp/ =========================