On Sat, Jun 19, 2010 at 06:45, Justin P. Mattock
<justinmattock(a)gmail.com> wrote:
> This is not dead code. NLMSG_NEW() sets up an nlmsg in
ab->skb.
> If you remove the code, it's no longer initialized.
I played around with this code some more, but am still getting confused with
nlmsg_new and NLMSG_NEW. if I remove the nlmsghdr struct I can get a clean
nlmsg_new() allocates a new nlmsg.
NLMSG_NEW() initializes a nlmsg inside an already allocated skbuff.
build without a warning, but still am a bit confused.
here is an updated patch let me know if it still needs work..
or if it's legit I can resend this.
Looks OK to me, thanks!
From 7515a08ba921d3beed33fa5c6b1fbe59cf52e069 Mon Sep 17 00:00:00
2001
From: Justin P. Mattock <justinmattock(a)gmail.com>
Date: Fri, 18 Jun 2010 19:44:30 -0700
Subject: [PATCH 4/4] audit
Signed-off-by: Justin P. Mattock <justinmattock(a)gmail.com>
---
kernel/audit.c | 3 +--
1 files changed, 1 insertions(+), 2 deletions(-)
diff --git a/kernel/audit.c b/kernel/audit.c
index c71bd26..1d51258 100644
--- a/kernel/audit.c
+++ b/kernel/audit.c
@@ -1041,7 +1041,6 @@ static struct audit_buffer * audit_buffer_alloc(struct
audit_context *ctx,
{
unsigned long flags;
struct audit_buffer *ab = NULL;
- struct nlmsghdr *nlh;
spin_lock_irqsave(&audit_freelist_lock, flags);
if (!list_empty(&audit_freelist)) {
@@ -1065,7 +1064,7 @@ static struct audit_buffer * audit_buffer_alloc(struct
audit_context *ctx,
if (!ab->skb)
goto nlmsg_failure;
- nlh = NLMSG_NEW(ab->skb, 0, 0, type, 0, 0);
+ NLMSG_NEW(ab->skb, 0, 0, type, 0, 0);
return ab;
--
1.7.1.rc1.21.gf3bd6
Gr{oetje,eeting}s,
Geert
--
Geert Uytterhoeven -- There's lots of Linux beyond ia32 -- geert(a)linux-m68k.org
In personal conversations with technical people, I call myself a hacker. But
when I'm talking to journalists I just say "programmer" or something like
that.
-- Linus Torvalds