On Sun, May 24, 2020 at 4:47 PM Gustavo A. R. Silva
<gustavoars(a)kernel.org> wrote:
One of the more common cases of allocation size calculations is
finding
the size of a structure that has a zero-sized array at the end, along
with memory for some number of elements for that array. For example:
struct audit_chunk {
...
struct node {
struct list_head list;
struct audit_tree *owner;
unsigned index; /* index; upper bit indicates 'will
prune' */
} owners[];
};
Make use of the struct_size() helper instead of an open-coded version
in order to avoid any potential type mistakes.
So, replace the following form:
offsetof(struct audit_chunk, owners) + count * sizeof(struct node);
with:
struct_size(chunk, owners, count)
This code was detected with the help of Coccinelle.
Signed-off-by: Gustavo A. R. Silva <gustavoars(a)kernel.org>
---
kernel/audit_tree.c | 4 +---
1 file changed, 1 insertion(+), 3 deletions(-)
Thanks, this looks reasonable to me, but it came in too late for the
v5.8 merge window (I dislike taking changes past -rc5/6 unless
critical). Once the merge window closes I'll merge this into
audit/next.
--
paul moore
www.paul-moore.com